Giai Thich vaneu ro cac pp xac dinh cac thong so trong cac cong thuc: UStx, us uon, k/c tam truc ,  modun trong bo truyen canh rang tru, rang thang , rang nghieng, bo truyen banh rang con va bo truyen truc vit. neu ro cach su dung cac cong thuc do'

* BRTRT:

US tiep xuc @h= (Zm.Zep.Zh/dw1)(can(2T1.(u+1).KHbeta.KHV/(u.bw)) <= [@H]

Zm he so xet den co tinh cua vl

neu banh rang bang thep' Zm= 276Mpa^1/2

Zep he so xet den tong chieu dai tiep xuc Zep=can((4-epw)/3)

ZH he so xet den hinh dang be mat tiep xuc

Zh=can(2/(sinaw))

T1 momen xoan tren br1

KHpeta he so tap trung tai trong

KHV he so tai trong dong

bw chieu' rong banh rong tai tam an khop

- US uon'

@F1=2T1.KF.YF1.Yep/(m.dw1.bw)<= [@F1]

@F2= YF2.@F1/YF1 <= [@F2]

KF= Kpanfa.Kpbeta.Kpv: cac thong so tai trong= KFpeta.KFV

YF he so dang rang phu thuoc vao so rang ve he so dich chinh

Yep He so ke den sai so do viec di chuyen diem luc

-k/c tam truc : aw >= 50.(u+1).canbac3(2.T1.KHbeta.KHV/(#banfa.u.[@H]^2)

" aw la aw ko phai anfaw"

#banfa= bw/aw= 2#bd/(u+1)

[@H]: US tx cho phep

- modun: 1,4.canbac3( T1.Kp.YF1/(#bd.Z1^2.[@F1]))

#bd=bw/dw he so chieu rong banh rang

* BRN

- UStx 

@H=(Zm.Zh.Zep/dw1)(can(2T1.KHanfa.KHbeta.KHV.(u+1)/(bw.u))

Zm he so xet den co tinh cua vat lieu

Zh he so xet den hinh dang be mat tiep xuc

Zh=can(2.cosbeta/(sin2anfatw)

" tw viet nho"

anfatw goc an khop trong mat mut banh rang nghieng doi voi bo truyen khong dich chinh anfatw=anfat

Zep he so xet den tong chieu dai tiep xuc

Zep= can (1/epanfa)

T1 momem xoan tren banh dan 1

KHV he so tai trong dong

KHanfa he so tai trong phan bo khong deu tai trong cac rang

KHbeta he so tap trung tai trong

- US uon

@F1= 2T1.Yep.Ybeta.YF1.Kp/(bw.dw1.mn) <= [@F1]

@F2= YF2.@F1/YF1 <= [@F2]

T1 mommen xoan tren banh dan 1

m modul phap

Yep=1/epanfa voi' epanfa he so trung khop ngang

Ybeta=1-beta/140 he so xet den anh huong goc nghieng

- k/c tam truc

aw= 43.(u+1).canbac3(T2.KHanfa.KHbeta.KHV/(#ba.u.[@H]^2)

- mudun

m>= 1,12.canbac3(T1.KF.YF1/(#bd.Z1td.[@F1]))

* BR con

- US tiep xuc

@H=ZH.Zm.Zep/d1)(can(2T1.KH.can(u^2+1)/0,85.u.b)) <= [@F1]

- US uon

@F1= 2T1.YF1.Yep.KF/(0,85d1.b.m) <=[@F1}

@[email protected]/YF1

* truc vit

- khoang cach truc

aw>=(Z2+q).canbac3((170/(Z2.[@H]))^2.T2.KH/q)

KH=KHbeta.KHV.KHanfa

- Us tiep xuc @H=(480/d2)(can(T2.KH/d1) <=[@H]

- US uon

@F=1,4 T2.YF.KFbeta.Kpv/(b2.d2.mn) <=[@F]

b2 chieu rong banh vit

YF he so dang rang

mn = m. cos beta